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2009
12-29

新手求助~一个关于链表的问题。。。

这个源代码网上找到的,是一个简单通信录的演示,可是我发现这个通信录在输入4条以上数据后,选择LIST列出所有项后,就会死循环地重复列某一个记录,请教该如何修改?
  谢谢了!
/*————————————————–华丽的分割线———————————————————————-*/

#include <stdio.h>
#include <stdlib.h>
struct address{
  char name[20];
  char street[20];
  char city[10];
  char state[10];
  char zip[7];
  struct address *next;
  struct address *prior;
  }list_entry;

struct address *start;
struct address *last;

void enter();
void display();
void search();
void save();
void load();
void list();

struct address *find(char *name);
struct address *dls_store(struct address *,struct address *);

main()
{
clrscr();
start=last=NULL;
load();
for (;;){
  switch(menu_select()){
    case 1:enter();break;
    case 2:delete();break;
    case 3:list();break;
    case 4:search();break;
    case 5:save();break;
    case 6:exit(0);
    }
  }
}

menu_select()
{
char c;
printf(“1.Enter\n”);
printf(“2.Delete\n”);
printf(“3.List\n”);
printf(“4.Search\n”);
printf(“5.Save\n”);
printf(“6.Quit\n”);
do{
  printf(“\nEnter you choice:”);
  c=getche();
  }while (c<’0′||c>’6′);
return c-48;
}

void enter()
{
struct address *info;
for (;;){
  info=(struct address *)malloc(sizeof(list_entry));
  if (!info){
    printf(“\nout of memory”);
  return;
  }
  inputs(“\nenter name:”,info->name,19);
  if (!info->name[0]) break;
  inputs(“enter street:”,info->street,19);
  inputs(“enter city:”,info->city,9);
  inputs(“enter state:”,info->state,9);
  inputs(“enter zip:”,info->zip,6);
  start=dls_store(info,start);
  }
}

inputs(char *prompt,char *s,int count)
{
char p[255];
do{
  printf(prompt);
  gets(p);
  if (strlen(p)>count) printf(“\ntoo long\n”);
  }while (strlen(p)>count);
  strcpy(s,p);
}

struct address *dls_store(struct address *i,struct address *top)
{
struct address *old,*p;
if (last==NULL){
  i->next=NULL;
  i->prior=NULL;
  last=i;
  return i;
  }
p=top;
old=NULL;
while(p){
  if (strcmp(p->name,i->name)<0){
    old=p;p=p->next;
    }
  else{
    if(p->prior){
      p->prior->next=i;
      i->next=p;
      i->prior=p->prior;
      p->prior=i;
      return top;
      }
    i->next=p;
    i->prior=NULL;
    p->prior=i;
    return i;
    }
  }
  old->next=i;
  i->next=NULL;
  i->prior=old;
  last=i;
  return start;
}

delete()
{
struct address *info;
char s[80];
printf(“enter name:”);
gets(s);
info=find(s);
if (info) {
  if (start==info){
    start=info->next;
    if (start)
      start->prior=NULL;
    else
      last=NULL;
    }
  else{
    info->prior->next=info->next;
    if(info!=last)
      info->prior->next=info->prior;
    else
      last=info->prior;
    }
  free(info);
  }
}

struct address *find(char *name)
{
struct address *info;
info=start;
while(info){
  if(!strcmp(name,info->name)) return info;
  info=info->next;
  }
printf(“name not found\n”);
return NULL;
}

void list()
{
struct address *info;
info=start;
printf(“\n%-20s%-20s%-10s%-10s%-6s\n”,
  ”姓名”,”街道”,”城市”,”省”,”邮编”);
while(info){
  display(info);
  info=info->next;
  }
printf(“\n\n”);
}

void display(struct address *info)
{
printf(“%-20s%-20s%-10s%-10s%-6s\n”,
  info->name,info->street,info->city,info->state,info->zip);
}

void search()
{
char name[40];
struct address *info,*find();
printf(“enter name to find:”);
gets(name);
info=find(name);
if(!info)
  printf(“not found\n”);
else
  display(info);
}

void save()
{
struct address *info;
FILE *fp;
if((fp=fopen(“mlist”,”wb”))==NULL){
  printf(“can not open file\n”);
  exit(1);
  }
printf(“\nSaving file\n”);
info=start;
while(info){
  fwrite(info,sizeof(struct address),1,fp);
  info=info->next;
  }
fclose(fp);
}

void load()
{
struct address *info,*temp=NULL;
FILE *fp;
if((fp=fopen(“mlist”,”rb”))==NULL){
  printf(“can not open file\n”);
  return;
  }
while(start){
  info=start->next;
  free(info);
  start=info;
  }
printf(“\nLoading file\n”);
start=(struct address *)malloc(sizeof(struct address));
if(!start){
  printf(“out of memory!\n”);
  return;
  }
info=start;
while(!feof(fp)){
  if(1!=fread(info,sizeof(struct address),1,fp)) break;
  info->next=(struct address *)malloc(sizeof(struct address));
  if (!info->next){
    printf(“out of memory\n”);
    return;
    }
  info->prior=temp;
  temp=info;
  info=info->next;
  }
temp->next=NULL;
last=temp;
start->prior=NULL;
fclose(fp);
}


新手求助~一个关于链表的问题。。。》有 0 条评论

  1. lxrmido 说:

    这个源代码网上找到的,是一个简单通信录的演示,可是我发现这个通信录在输入4条以上数据后,选择LIST列出所有项后,就会死循环地重复列某一个记录,请教该如何修改?
    http://bbs.bccn.net/images/smilies/emot/em09.gif','Image‘);” onmouseover=”this.style.cursor=’hand’” onmouseout=”this.style.cursor=”” src=”http://bbs.bccn.net/images/smilies/emot/em09.gif” border=”0″ />  谢谢了!
    /*————————————————–华丽的分割线———————————————————————-*/

    #include <stdio.h>
    #include <stdlib.h>
    struct address{
      char name[20];
      char street[20];
      char city[10];
      char state[10];
      char zip[7];
      struct address *next;
      struct address *prior;
      }list_entry;

    struct address *start;
    struct address *last;

    void enter();
    void display();
    void search();
    void save();
    void load();
    void list();

    struct address *find(char *name);
    struct address *dls_store(struct address *,struct address *);

    main()
    {
    clrscr();
    start=last=NULL;
    load();
    for (;;){
      switch(menu_select()){
        case 1:enter();break;
        case 2:delete();break;
        case 3:list();break;
        case 4:search();break;
        case 5:save();break;
        case 6:exit(0);
        }
      }
    }

    menu_select()
    {
    char c;
    printf(“1.Enter\n”);
    printf(“2.Delete\n”);
    printf(“3.List\n”);
    printf(“4.Search\n”);
    printf(“5.Save\n”);
    printf(“6.Quit\n”);
    do{
      printf(“\nEnter you choice:”);
      c=getche();
      }while (c<’0′||c>’6′);
    return c-48;
    }

    void enter()
    {
    struct address *info;
    for (;;){
      info=(struct address *)malloc(sizeof(list_entry));
      if (!info){
        printf(“\nout of memory”);
      return;
      }
      inputs(“\nenter name:”,info->name,19);
      if (!info->name[0]) break;
      inputs(“enter street:”,info->street,19);
      inputs(“enter city:”,info->city,9);
      inputs(“enter state:”,info->state,9);
      inputs(“enter zip:”,info->zip,6);
      start=dls_store(info,start);
      }
    }

    inputs(char *prompt,char *s,int count)
    {
    char p[255];
    do{
      printf(prompt);
      gets(p);
      if (strlen(p)>count) printf(“\ntoo long\n”);
      }while (strlen(p)>count);
      strcpy(s,p);
    }

    struct address *dls_store(struct address *i,struct address *top)
    {
    struct address *old,*p;
    if (last==NULL){
      i->next=NULL;
      i->prior=NULL;
      last=i;
      return i;
      }
    p=top;
    old=NULL;
    while(p){
      if (strcmp(p->name,i->name)<0){
        old=p;p=p->next;
        }
      else{
        if(p->prior){
          p->prior->next=i;
          i->next=p;
          i->prior=p->prior;
          p->prior=i;
          return top;
          }
        i->next=p;
        i->prior=NULL;
        p->prior=i;
        return i;
        }
      }
      old->next=i;
      i->next=NULL;
      i->prior=old;
      last=i;
      return start;
    }

    delete()
    {
    struct address *info;
    char s[80];
    printf(“enter name:”);
    gets(s);
    info=find(s);
    if (info) {
      if (start==info){
        start=info->next;
        if (start)
          start->prior=NULL;
        else
          last=NULL;
        }
      else{
        info->prior->next=info->next;
        if(info!=last)
          info->prior->next=info->prior;
        else
          last=info->prior;
        }
      free(info);
      }
    }

    struct address *find(char *name)
    {
    struct address *info;
    info=start;
    while(info){
      if(!strcmp(name,info->name)) return info;
      info=info->next;
      }
    printf(“name not found\n”);
    return NULL;
    }

    void list()
    {
    struct address *info;
    info=start;
    printf(“\n%-20s%-20s%-10s%-10s%-6s\n”,
      ”姓名”,”街道”,”城市”,”省”,”邮编”);
    while(info){
      display(info);
      info=info->next;
      }
    printf(“\n\n”);
    }

    void display(struct address *info)
    {
    printf(“%-20s%-20s%-10s%-10s%-6s\n”,
      info->name,info->street,info->city,info->state,info->zip);
    }

    void search()
    {
    char name[40];
    struct address *info,*find();
    printf(“enter name to find:”);
    gets(name);
    info=find(name);
    if(!info)
      printf(“not found\n”);
    else
      display(info);
    }

    void save()
    {
    struct address *info;
    FILE *fp;
    if((fp=fopen(“mlist”,”wb”))==NULL){
      printf(“can not open file\n”);
      exit(1);
      }
    printf(“\nSaving file\n”);
    info=start;
    while(info){
      fwrite(info,sizeof(struct address),1,fp);
      info=info->next;
      }
    fclose(fp);
    }

    void load()
    {
    struct address *info,*temp=NULL;
    FILE *fp;
    if((fp=fopen(“mlist”,”rb”))==NULL){
      printf(“can not open file\n”);
      return;
      }
    while(start){
      info=start->next;
      free(info);
      start=info;
      }
    printf(“\nLoading file\n”);
    start=(struct address *)malloc(sizeof(struct address));
    if(!start){
      printf(“out of memory!\n”);
      return;
      }
    info=start;
    while(!feof(fp)){
      if(1!=fread(info,sizeof(struct address),1,fp)) break;
      info->next=(struct address *)malloc(sizeof(struct address));
      if (!info->next){
        printf(“out of memory\n”);
        return;
        }
      info->prior=temp;
      temp=info;
      info=info->next;
      }
    temp->next=NULL;
    last=temp;
    start->prior=NULL;
    fclose(fp);
    }

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